Answer: X = 5m, Y = 20m, Z = 45m
Step-by-step explanation:
1) See attached the figure of this problem (missing in your question).
2) The equation that models the height with initial velocity Voy, in absence of gravity (dashed line) is:
H = Voy × t
3) The equation that models the height with initial velocity Voy and with gravity (parabola) is:
H' = Voy×t - g×t² / 2
4) The lengths requested correspond to the diffference in heights:
H - H' = g×t² / 2
5) Using g = 10 m/s²
H- H' = 5t²
6) X, Y and Z are at t = 1 s, t = 2 s, and t = 3 s
X = 5m/s² × (1s)² = 5 m
Y = 5m/s² × (2s)² = 20 m
Z = 5m/s² × (3s)² = 45 m