Question

To what volume in millimeters must 50.0 mL of 18.0 M H2SO4 be diluted to obtain 4.35 M H2SO4?

Answer 1

We know that to relate solutions of with the factors of molarity and volume, we can use the equation:
`M_(1) V_(1) = M_(2) V_(2)`

**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.

So now we can assign values to these variables. Let us say that the 18 M
`H_(2) SO_(4)` is the left side of the equation. Then we have:


`(18 M)(0.050 L)=(4.35M) V_(2)`

We can then solve for
`V_(2)`:


`V_(2)= ((18M)(0.05L))/(4.35M)` and
`V_(2) =0.21 L` or
`210 mL`

We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.