Question

PLEASE HELP

What is the specific heat of a substance if 300 J are required to raise the temperature of a 267–g sample by 12ºC? show your work

Answer 1

Answer:
Cp = 0.093 J.g⁻¹.°C⁻¹
Solution:

The equation used for this problem is as follow,

Q = m Cp ΔT ----- (1)

Where;
Q = Heat = 300 J

m = mass = 267 g

Cp = Specific Heat Capacity = ??

ΔT = Change in Temperature = 12 °C

Solving eq. 1 for Cp,

Cp = Q / m ΔT


Putting values,
Cp = 300 J / (267 g × 12 °C)

Cp = 0.093 J.g⁻¹.°C⁻¹