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If 35 J of work was performed in 70 seconds, how much power was used to do this task?
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Feb 19, 2019
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If 35 J of work was performed in 70 seconds, how much power was used to do this task?
Physics
middle-school
Kyle Carlson
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P = Power
W = Work
Delta T = Change of Time
So:
P = 35 Joules
Delta T = 70 secs
W = ?
* Joule/Sec = Watt
Answer: The power used to do this task was 0.5 Watts.
Sod Almighty
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Feb 25, 2019
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Sod Almighty
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