Question

To approach the runway, a pilot of a small plane must begin a 10* descent starting from a height of 1,790 feet above ground. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach? A. 2.0 mi B. 0.3 Mi C. 1.7 mi D. 10,308.2 mi

Answer 1

2.0 mi

Explanation:

x = depression

`sin10° = (1790ft)/(x)` Use sine ratio.

`x = (1790ft)/(sin10°)` Use calculator to find sin10° and simplify for x.

`x = (1790ft)/(0.17364817766693034885171662676931)`

`x = 10,308.199164827104029827422425645ft`

*NEED TO CONVERT FT TO MILES*

1 mile = 5280 ft. Substitute ft for mi

`(10,308.199164827104029827422425645 ft )/(5280ft) = 1.9523104478839212177703451563722 mi`

= 2.0 mi rounded to nearest tenth

Answer 2

since there are 5280 feet in 1 mile, in 1790 feet, there are 1790/5280 miles, or about 0.339 miles.

check the picture below.

make sure your calculator is in Degree mode.