Question

The one-to-one functions g and h are defined as follows.

g={(-9,-4),(-7,3),(0,-6),(8,0)
h(x)=4x+9

I need to know what g^-1(0) is. I need help!

Answer 1

`g^(-1)(0) = 8`

Step-by-step explanation:

Given

`g=\{(-9,-4),(-7,3),(0,-6),(8,0)\}`

`h(x) = 4x + 9`

Required

Find
`g^(-1)(0)`

A relation is represented as:
`(x,y)`

And the following relationships exist between x and y

`y = g(x)`

and

`x =g^(-1)(y)`

So:
`g^(-1)(0)` implies that:

`x = g^(-1)(0)`

Which means that: we look for the corresponding value of x where y = 0.

Hence:

`x = g^(-1)(0) = 8`

`g^(-1)(0) = 8`