Question

I NEED FAST HELP

What is the specific heat of a substance if 300 J are required to raise the temperature of a 267–g sample by 12ºC? Show work

Answer 1

Amount of heat per unit mass required to raise the temperature by one degree Celsius is referred as specific heat. Mathematically, it is expressed as

q = mcΔT

where
q = heat energy
m = mass
c = specific heat
ΔT = change in temperature


Given: q = 300 J, m = 267 g, ΔT = 12 oC

∴ c = 300/(267 X 12) = 0.9363 J/g oC

Thus, specific heat of material is 0.09363 J/g oC

Answer 2

We can use the heat equation,
Q = mcΔT

Where,

Q = the amount of energy transferred (J)

m = the mass of the substance (kg)

c = the specific heat (J g⁻¹ °C⁻¹)

ΔT = the temperature difference (°C).

According to the given data for the substance,

Q = 300 J

m = 267 g

c = ?
ΔT = 12 °C

From substitution,

300 J = 267 g x c x 12 °C
c = 0.0936 J g⁻¹ °C⁻¹

Hence, specific heat of the given substance is 0.0936 J g⁻¹ °C⁻¹.