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Solve the equation for x, where x is a real number (5 points):
3x^2 + 2x + 15 = 0

1 Answer

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To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 +bx + c = 0
x = [ -b ± √(b^2-4ac) ] /(2a)
x = [-2 ± √((2)^2 - 4(3)(15)) ] / ( 2(3) )
x = [-2 ± √(4- (180) ) ] / ( 6 )
x = [-2 ± √(-176) ] / ( 6)
Since √-176 is nonreal, the answer to this question is that there are no real solutions.
User Brian Rizo
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