50.9k views
3 votes
Solve the equation for x, where x is a real number (5 points):
3x^2 + 2x + 15 = 0

1 Answer

4 votes
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 +bx + c = 0
x = [ -b ± √(b^2-4ac) ] /(2a)
x = [-2 ± √((2)^2 - 4(3)(15)) ] / ( 2(3) )
x = [-2 ± √(4- (180) ) ] / ( 6 )
x = [-2 ± √(-176) ] / ( 6)
Since √-176 is nonreal, the answer to this question is that there are no real solutions.
User Brian Rizo
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories