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The sears tower in chicago is 1454 feet high. sketch and find the angle of elevation from a point 750 feet from the base to the top of the tower. relate your answer to the nearest tenth.

2 Answers

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The tower will be represented by AB and BC is the base of the tower to the point 750 ft. The angle of elevation is α.
the value of α will be given by:
tan α=(AB)/(BC)
AB=1454 ft
BC=750 ft
hence:
tan α=750/1454
tan α=0.5158
thus
α=arctan 0.5158
α=27.2855~27.3°
The sears tower in chicago is 1454 feet high. sketch and find the angle of elevation-example-1
User Rcoyner
by
5.4k points
7 votes

Answer:

The correct answer is 62.7

Explanation:

Use tan (tan= opp/adj)

Input your values:

Height- 1454

Length from Base- 750

Equation:

tan(x)=1454/750 (Gives you 1.938...)

The use the inverse of tan and use 1.938

Equation:

atan(1.938)= 62.07

Hope this helped you out :}

User Alswl
by
5.5k points