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How do you evaluate #g(10)# given #g(x)=-3x+1#?
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How do you evaluate #g(10)# given #g(x)=-3x+1#?

User Pavan Sokke Nagaraj
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Just substitute 10 for x in g(x)=-3x+1: g(10) = -3(10) + 1 = -29 (answer)
User Montycarlo
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