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How do you determine the Vertex as an ordered pair when #f(x)=3(x+2)^2-1#?
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How do you determine the Vertex as an ordered pair when #f(x)=3(x+2)^2-1#?

User John Alley
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The function is in vertex form: y = a(x - h)² + k where (h, k) is the vertex

Based on the vertex form: h = -2 and k = -1
Vertex (-2, -1)
User Ateev Chopra
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