Question

A triangle has sides with lengths: 6, 9, and 5. How do you find the area of the triangle using Heron's formula?

Answer 1

Area of triangle=Δ=√s(s-a)(s-b)(s-c)
a=6
b=9
c=5
s=(a+b+c)/2
s=(6+9+5)/2
s=10
Δ=√10(10-6)(10-9)(10-5)
Δ=10√2 sq. units
OR
Δ=14.14 sq. units