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Which function has a range of (−90°, 90°)? A) f(x) = sin−1(x) B) f(x) = cos−1(x) C) f(x) = tan−1(x) D) f(x) = sec−1(x) A is the answer.
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May 10, 2019
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Which function has a range of (−90°, 90°)?
A) f(x) = sin−1(x)
B) f(x) = cos−1(x)
C) f(x) = tan−1(x)
D) f(x) = sec−1(x)
A is the answer.
Mathematics
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Estel
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Yes you are right because only sin⁻¹(x) is Bijective in the given range.
Option A is correct
Honk
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May 15, 2019
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