Question

An electrolyte solution has an average current density of 111 ampere per square decimeter \left( \dfrac{\text{A}}{\text{dm}^2}\right)( dm 2 A ​ )left parenthesis, start fraction, A, divided by, d, m, start superscript, 2, end superscript, end fraction, right parenthesis. What is the current density of the solution in \dfrac{\text{A}}{\text{m}^2} m 2 A ​ start fraction, A, divided by, m, start superscript, 2, end superscript, end fraction?

Answer 1

Answer is 100

Explanation:

Answer 2

Average current density of the solution = 1 ampere per square decimeter

We have to find the average current density of the solution in ampere per square meter.

1 decimeter =
`(1)/(10)` meter
Squaring both sides we get

1 decimeter square =
`(1)/(100)` meter square

Current density =
`1 (A)/(dm^(2) ) =1 (A)/( (1)/(100) m^(2) ) =100Am^(-2)`

Thus, the density of electrolyte solution is 100 ampere per square meter