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In rectangle ABCD, the angle bisector of ∠A intersects side

DC
at point M and the angle bisector of ∠C intersects side
AB
at point N. The length of
CM
is equal to the length of
AM
and it is 6 in longer than the length of
DM
. Find the perimeter of quadrilateral ANCM.

2 Answers

2 votes

Answer:

P=48+24
√(2)\\ in.

Explanation:

User Ankakusu
by
6.4k points
1 vote
48+24 square two
DM=AD (45, 45,90)
Use pythagorean theorum to find x
(x-6)^2+(x-6)^2=x^2
you get
(12+6 (root)2)
since all the sides are the same you multiply that by four

User MJZ
by
6.4k points