Question

How do you find the x-intercepts of

`y = 12x + {7x}^(2)`
Please help!!

Answer 1

x - intercepts → y = 0


`y=12x+7x^2\to12x+7x^2=0\\\\x(12+7x)=0\iff x=0\ \vee\ 12+7x=0\\\\x=0\ \vee\ 7x=-12\\\\x=0\ \vee\ x=-(12)/(7)`

Answer:
`x=0;\ x=-(12)/(7)`