Question

Georgia is jogging with a velocity of 4 m/s when she accelerates at 2 m/s2 for 3 seconds. How fast is Georgia running now?

Answer 1

Georgia is moving by uniformly accelerated motion, with initial velocity

`v_0 =4 m/s`
and with constant acceleration of

`a=2 m/s^2`
so her velocity at time t is given by

`v(t) = v_0 + at = 4 m/s + (2 m/s^2)(3 s)= 10 m/s`
So now Georgia is running at 10 m/s.