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4 votes
Determine the number of moles of al needed to completely react with 9.0 moles of ni2

User Mastef
by
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1 Answer

4 votes
Answer: 6.0 moles

Step-by-step explanation:

1) The information in the quesiton is incomplete.

2) The question is bases on a voltaic cell in which the reactants are

Al (NO₃) ₃ (aq) + Ni (NO₃) ₂ (aq).

3) And you are also given the net ionic reaction:
2Al(s) + 3Ni²⁺ (aq) → 2Al₃ (aq) + 3Ni(s)



4) It is from the net ionic reaction that you get the ration between Al and Ni:
2 moles of Al react with 3 moles of Ni, so you can state the proportion:

2 moles Al / 3 moles Ni = x / 9.0 moles Ni


5) So, you just must solve for x:

x = 9.0 moles Ni × 2 moles Al / 3 mols Ni = 6.0 moles Al


User Angel Guillen
by
7.8k points
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