Question

14 part a and b. While at the park, you decide to purchase a hamburger for $3.26 and 3 bottles of water. If you purchase the hamburger and 3 bottles of water, pay with a $9.50 bill, and receive no change, then how much did each bottle of water cost? You are required to answer the following parts. Part A - Write and solve the equation

Answer 1

`3.26 + 3B = 9.50`

A bottle water costs $2.08

Step-by-step explanation:

Given

Represent the hamburger with H

Represent the bottles of water with B

`Total = \$9.50`

Solving (a): Represent as an equation

1 hamburger = 3.26

3 bottles of water = 3 * B

Total = 9.50

The system is represented as thus:

1 hamburger + 3 bottles of water = Total

Substitute values

`3.26 + 3 * B = 9.50`

`3.26 + 3B = 9.50`

Solving (b): The cost of bottle water

`3.26 + 3B = 9.50`

Make 3B the subject

`3B = 9.50 - 3.26`

`3B = 6.24`

Divide both sides by 3

`(3B)/(3) = (6.24)/(3)`

`B = (6.24)/(3)`

`B = 2.08`

A bottle water costs $2.08