check the picture below.
so, to get the area of the triangles, we can simply run a perpendicular line from the top to the base, and end up with a right-triangle with a base of 22 and a hypotenuse of 34, let's find the altitude.

so then the surface area of the triangular prism is,
![\bf \stackrel{\textit{left and right}}{2(34\cdot 76)}~~+~~\stackrel{\textit{bottom}}{(44\cdot 76)}~~+~~\stackrel{\textit{front and back}}{2\left[\cfrac{1}{2}(44)(√(672)) \right]} \\\\\\ 8512~~+~~(44)(√(672))\qquad \approx\qquad 9652.61036291978](https://img.qammunity.org/2019/formulas/mathematics/high-school/4ac9m0g9qk39yplpvxghx7wffd78fmlnd9.png)