Answer:
![(49)/(169)](https://img.qammunity.org/2019/formulas/mathematics/high-school/agzxpmjeruqrxb80fre995u75p51y5n8ag.png)
Explanation:
Given: Number of fiction books = 7
Number of nonfiction books = 6
Probability of fiction books =
![\frac{\text{Number of fiction book}}{\text{Total book}}=(7)/(13)](https://img.qammunity.org/2019/formulas/mathematics/high-school/4vlqqhlg1stodkd2h27juiegqv26ttioe5.png)
Since , Paul randomly selects one puts it back.
Then the number of books remains same and events will be independent.
Now, if he randomly selects another then the probability that both selections were fiction books will be:
![(7)/(13)*(7)/(13)=(49)/(169)](https://img.qammunity.org/2019/formulas/mathematics/high-school/qw99i6zqisy8u2wsl7phor7qins3pti49b.png)
Hence, the required probability =
![(49)/(169)](https://img.qammunity.org/2019/formulas/mathematics/high-school/agzxpmjeruqrxb80fre995u75p51y5n8ag.png)