Question

How many solutions does this equation have?
2y+20y-15=19+20y

Answer 1

1 solution

Explanation:

2y + 20y - 15 = 19 + 20y , that is

22y - 15 = 19 + 20y ( subtract 20y from both sides )

2y - 15 = 19 ( add 15 to both sides )

2y = 34 ( divide both sides by 2 )

y = 17

Answer 2

Explanation:

Answer

one

Proof

2y + 20y - 15 = 19 + 20y Combine the left side.

22y - 15 = 19 + 20y Add 15 to both sides

22y - 15+15 = 19 +15 + 20y Combine

22y = 34 + 20y Subtract 20y from booth sides

22y-20y = 34 + 20y-20y Combine

2y = 34 Divide both sides by 2

2y/2 = 34/2

y = 17

That's the only solution you get. The number of solutions to any equation (with certain exceptions) is the highest power on the variable.

x^2 + 2x - 8 has 2 solutions (from the x^2)

x^3 + 3x^2 + 2x + 15 = y has three solutions