Question

What is the domain of the function y=sqrt x+4

Answer 1

`\text{if}\ y=√(x)+4\ \text{then the domain is}\ x\geq0\to x\in\mathbb{R^+}\cup\{0\}`



`\text{if}\ y=√(x+4)\ \text{then the domain is}\ x+4\geq0\to x\geq-4\to x\in\left<-4;\ \infty\right)`

Answer 2

Domain of
`√(x+4)` is [-4,∞)

Explanation:

We have to find domain of
`√(x+4)`

We know that the square root value of negative numbers are not defined.

So we should not give negative numbers inside square root.

That is

`x+4\geq 0\\\\x\geq -4`

Domain of
`√(x+4)` is [-4,∞)