Question

3h/h^2-12h+36 -18/h^2-12h+36

Answer 1

The equation: 3h/h^2-12h+36 -18/h^2-12h+36 have the same denominator, we will just subtract the numerators
3h/h^2-12h+36- 18/h^2-12h+36=3h-18/h^2-12h+36
Let us factor the common termsx(h-6)/h^2-12h+36= 3(h-6)/(h-6)^2
So since h-6 are similar, we can cancel the numerator and cancel 1 term in the denominatorso,3(h-6)/(h-6)^2=3/h-6
SO the answer of 3h/h^2-12h+36 -18/h^2-12h+36 is 3/h-6

Answer 2

Since both fractions have the same denominator, we just need to subtract the numerators:

`(3h)/(h^2-12h+36) - (18)/(h^2-12h+36) = (3h-18)/(h^2-12h+36)`

Notice that we have a common factor, 3, in the numerator, so lets factor that out:

`(3h-18)/(h^2-12h+36)= (3(h-6))/(h^2-12h+36)`

Next, we can factor the denominator:

`(3(h-6))/(h^2-12h+36) = (3(h-6))/((h-6)^2)`

Now we can cancel the common factor
`h-6` in both numerator and denominator:

`(3(h-6))/((h-6)^2)= (3)/(h-6)`

We can conclude that the result of 3h/h^2-12h+36 -18/h^2-12h+36 is:
`(3)/(h-6)`