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Given: KLMN is a rectangle m∠NKM = 58° MP −∠ bisector of ∠KML Find: m∠KPM

User Bschultz
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According to the rule of angles and parallel lines, we can say that ∠NKM and ∠KML are equal because they are alternate angles. Since MP is a bisector, ∠KMP = ∠LMP = 1/2∠NKM = 29°. We know that ∠MKL = 90°-∠NKM = 32°. According to the sum of all angles of the triangle, ∠KPM = 180-(32+29) = 119°.
Given: KLMN is a rectangle m∠NKM = 58° MP −∠ bisector of ∠KML Find: m∠KPM-example-1
User LiCheng
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