Simplify (4y^2-13y+3)/2y^2-5y-12 multiplied by (2y^2+9y+9)/16y^2-1) Multiplied by (Y^2+3y-28)/y^2-9)

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Zelanix · Answer 1 · 2019-02-26T18:48:40+0000

After factoring each polynomial and canceling the resulting binomials that appear in both the numerator and denominator, you are left with this fraction for your answer:

(y+7)/(4y+1)

Simplify (4y^2-13y+3)/2y^2-5y-12 multiplied by (2y^2+9y+9)/16y^2-1) Multiplied by (Y^2+3y-28)/y^2-9)

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