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Simplify (4y^2-13y+3)/2y^2-5y-12 multiplied by (2y^2+9y+9)/16y^2-1) Multiplied by (Y^2+3y-28)/y^2-9)
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2 votes
Simplify

(4y^2-13y+3)/2y^2-5y-12 multiplied by
(2y^2+9y+9)/16y^2-1) Multiplied by
(Y^2+3y-28)/y^2-9)

User Rashard
by
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1 Answer

6 votes
After factoring each polynomial and canceling the resulting binomials that appear in both the numerator and denominator, you are left with this fraction for your answer:


(y+7)/(4y+1)


User Zelanix
by
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