Question

The height of the Eiffel Tower is 1050 feet. From the top, the angle of depression to a soccer ball on the ground is 20 degrees. Find, to the nearest foot, the distance from the soccer ball to the base of the Eiffel Tower.

Answer 1

Since the angle of depression from the Eiffel tower is congruent to the angle of elevation from the soccer ball, the angle of elevation from the soccer field is 20°

Now, we can use the trigonometric function tangent to find the distance from the soccer ball to the base of the Eiffel Tower:

`tan( \alpha )= (opposite.side)/(adjacent.side)`

`tan(20)= (1050)/(a)`

`a= (1050)/(tan(20))`

`a=2884.85`

We can conclude that the distance from the soccer ball to the base of the Eiffel Tower is 2884.85 feet.