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Which series of transformations results in the image being congruent to the pre-image?

(x, y) → (x, –y)
(x, y) → (x + 5, y)
(x, y) → (–x, y)

(x, y) → (x + 1, y)
(x, y) → (–x, –y)
(x, y) → (2x, y)

(x, y) → (0.5x, 0.5y)
(x, y) → (x, –y)
(x, y) → (x, y + 8)

(x, y) → (x – 4, y)
(x, y) → (x, y + 3)
(x, y) → (3x, 3y)

User Agstudy
by
5.6k points

2 Answers

1 vote

Answer:

"images of transformation are congurent if they were translates, mirrored/flipped or rotated

1) (x, y) → (x, –y) flipped

(x, y) → (x + 5, y) translated

(x, y) → (–x, y) flipped

->is congruent

2) (x, y) → (x + 1, y) translated

(x, y) → (–x, –y) flipped

(x, y) → (2x, y) scaled->not congruent

3) (x, y) → (0.5x, 0.5y) scaled-> not congurent

(x, y) → (x, –y)

(x, y) → (x, y + 8)

4) (x, y) → (x – 4, y) translated

(x, y) → (x, y + 3) translated

(x, y) → (3x, 3y) scaled->not congruent

so only the first series of transformations has congruent after image"

Explanation:

User Joshnuss
by
6.6k points
1 vote
images of transformation are congurent if they were translates, mirrored/flipped or rotated
1)
(x, y) → (x, –y) flipped
(x, y) → (x + 5, y) translated
(x, y) → (–x, y) flipped
->is congruent
2)
(x, y) → (x + 1, y) translated
(x, y) → (–x, –y) flipped
(x, y) → (2x, y) scaled->not congruent
3)
(x, y) → (0.5x, 0.5y) scaled-> not congurent
(x, y) → (x, –y)
(x, y) → (x, y + 8)
4)
(x, y) → (x – 4, y) translated
(x, y) → (x, y + 3) translated
(x, y) → (3x, 3y) scaled->not congruent

so only the first series of transformations has congruent after image
User Leo Valeriano
by
6.3k points
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