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2 votes
Complement of a set

3x^(2) - 2x - 8 \geqslant 0
is?

1 Answer

5 votes

3x^2-2x-8 \geq 0


(x-2)(3x+4) \geq 0


3x+4\geq 0 \mbox{ and } x-2\geq 0


x\leq -(4)/(3) \mbox{ or } x\geq 2

the complement of this set is:


-(4)/(3) \ \textless \ x \ \textless \ 2




User Ben Fortune
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