Question

If an aqueous solution has a ph of 5.57 what is the concentration of hydroxide ion ([oh-]) in the solution?

Answer 1

pH=5.57
pH+pOH=14
5.57 + pOH=14
pOH = 14-5.57= 8.43

pOH = - log [OH⁻]
-pOH= log [OH⁻]



`[OH^(-)] = 10^(-pOH)= 10^(-8.43)= 3.72*10^(-9) [OH^(-)]= 3.72*10^(-9)`