Question

A ball is thrown into the air with an upward velocity of 32 ft/s. Its height h in feet after t seconds is given by the function h=-16t^(2)+32t+6. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?

Answer 1

Max height occurs when speed equals zero

v = dh/dt = -32t +32
Hence when v=0, t=1 sec
Max height = 24 ft