Question

A bus starting from rest moves with a uniform acceleration of 0.1 ms ^-2 for 2 minutes.Find the speed acquired then find the distance travelled

Answer 1

1) Speed acquired
The time taken for the motion is

`t=2 min=2 \cdot 60 = 120 s`
The bus is moving by uniformly accelerated motion, with constant acceleration
`a=0.1 m/s^2`, so the speed acquired by the bus after 120 s is

`v(t) = at=(0.1 m/s^2)(120 s)=12 m/s`

2) The distance traveled is given by the following formula:

`S= (1)/(2)at^2`
where a is the acceleration and t the time. Substituting numbers into the equation, we find

`S= (1)/(2)(0.1 m/s^2)(120 s)^2=720 m`