From the information given;
P(cold) = 0.4
P(no cold) = 1-0.4 = 0.6
The number of ways of selecting 4 from 10 = 10C4 = 210
Probability that the 4 selected with catch a cold:
P(4 will catch cold) = (10C4)*P(cold)^4*P(no cold)^6 = 210*0.4^4*0.6^6 = 0.2508