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How do you find the axis of symmetry in the quadratic equation x²+4x+4=0
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How do you find the axis of symmetry in the quadratic equation x²+4x+4=0

User Patzm
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The equation of a parabola is y=a(x-p)^2+q, where (p,q) are the coordinates of the vertex. The value of p will be your axis of symmetry.

(x+2)^2=0

In order for 0=0

x=-2

So your axis of symmetry is x=-2
User Ginchen
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