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What are the coordinates of the point that corresponds to -7x/4 on the unit circle

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This is a problem of intersection. So, we have two equations, first of all we have a straight line and the second equation is a circle with ratio equal to 1. Therefore, in a mathematical language this is established as follows:

(1)
y = (-7x)/(4)
(2)
x^(2)+y^(2)=1

We introduce (1) into (2):


x^(2)+((-7x)/(4))^(2)=1

x^(2)+(49x)/(16)^(2)=1

65x^(2)=16

There are two values, namely:


\left \{ {{x_(1) = +0.4961 } \atop {x_(2) = -0.4961 }} \right.

Then, substituing these values in the first (1) equation, we find:


\left \{ {{y_(1) = -0.8681 } \atop {y_(2) = +0.8681 }} \right.

Finally, the points are two:


P_(1)=(0.4961,-0.8681)

P_(2)=(-0.4961,0.8681)
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