Question

Which quadratic equation defines the function that has zeros at − 1/12 and 1/4 ?

Answer 1

22

Explanation:

Answer 2

`\bf \begin{cases} x=-(1)/(2)\implies &x+(1)/(2)=0\\\\ x=(1)/(4)\implies &x-(1)/(4)=0 \end{cases} \\\\\\ \left( x+(1)/(2) \right)\left( x-(1)/(4) \right)=\stackrel{y}{0}\implies \stackrel{FOIL}{x^2+(1)/(4)x-(1)/(8)}=y`