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QF Q2.) Solve the triangle
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QF Q2.) Solve the triangle

QF Q2.) Solve the triangle-example-1
User Gtomer
by
7.6k points

2 Answers

4 votes
C=180-A-B=180-67-53=60deg.

by sine rule

b/sinB=a/sinA
b=a/sinA*sinB
=13/sin(67)*sin(53)
= 11.28

c/sinC=a/sinA
c=a/sinA*sinC
=13/sin(67)*sin(60)
= 12.23

User David Rauca
by
8.1k points
6 votes
60°
11
12

see photo for soln
QF Q2.) Solve the triangle-example-1
User Yotam Hadas
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8.6k points
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