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Factor by grouping: 2v^3 + 3v^2 + 4v + 6

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2v^3 + 3v^2 + 4v + 6
= (2v^3 + 3v^2) + (4v + 6)
= v^2 (2v + 3) + 2 (2v + 3)
= (v^2 + 2)(2v + 3)

hope it helps
User Yurii Kramarenko
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