Question

Write the standard form of the equation of the circle with the given center and radius.

(-3, 6); 10

Answer 1

The std eqn is (x-h)^2 + (y-k)^2 = r^2.

Here we have (x+3)^2 + (y-6)^2 = 10^2 (answer)

Answer 2

A circle with center at (-3, 6) and a radius of 10 has the following standard form equation

`(x+3)^2+(y-6)^2=100`

Explanation:

This is the general standard equation for the circle centered at (h, k) with radius r

`(x-h)^2+(y-k)^2=r^2`

It shows all the important information at a glance: the center (h, k) and the radius r.

A circle with center at (-3, 6) and a radius of 10 has the following standard form equation

Start with:

`(x-h)^2+(y-k)^2=r^2`

Put in (h, k) and r

`(x-(-3))^2+(y-6)^2=10^2\\(x+3)^2+(y-6)^2=100`