Question

What is the surface area of the right cone below?

A. 248pi
B. 304pi
C. 184pi
D. 496pi

Answer 1

SA = pi*r^2 + pi*r*l
SA = pi[8^2 + 8(15)]
SA = 184 pi units^2

Answer 2

Option C is correct

`184 \pi` square units.

Explanation:

Surface area of cone(S) is given by:

`S = \pi r(r +l)` ....[1]

where,

r is the radius of the cone

l is the slant height of the cone.

As per the statement:

From the given diagram of cone:

radius of the cone(r) = 8 units

Slant height(l) = 15 units

Substitute in [1] we have;

`S = \pi \cdot 8 \cdot (8+15)`

⇒
`S = \pi \cdot 8 \cdot (23)`

⇒
`S = 184 \pi` square units.

Therefore, the surface area of the right cone is,
`184 \pi` square units.