First, we are going to find the distance traveled by the ship adding the tow distances:
Distance traveled= 24 mi +33 mi=57 mi
Next, we are going to use the Pythagorean theorem to find the distance from
![a](https://img.qammunity.org/2019/formulas/mathematics/middle-school/29wl7w45fjbhkymu53hsles9qvadja8y1s.png)
to
![c](https://img.qammunity.org/2019/formulas/mathematics/middle-school/9noujvlad80s1vjnwm1kln023au43wyqwx.png)
:
![d^2=24^2+33^2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/lbje3hjhb55he2a090gia4iqhlycid93tg.png)
![d^2=576+1089](https://img.qammunity.org/2019/formulas/mathematics/middle-school/h0qzw8cuwpi8rq85xx3duldvkfl7hqi185.png)
d^2=1665
![d= √(1665)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/8dagth9dbmzk4w7wksfiovhdhgf1jcpyms.png)
![d=40.8](https://img.qammunity.org/2019/formulas/mathematics/middle-school/2uhfhi6ro9efyt8i72eakdke4ybcw49t9b.png)
mi
Finally, we are going to subtract the two distances:
57 mi -40.8 mi= 16.2 mi
We can conclude that
if the ship could have traveled in a straight lime from point a to point c, it could have saved 16.2 miles.