Question

What is the power of a machine that pushes with a force of 3 n for a distance of 9 m in 8 s?

Answer 1

The work done by the machine is equal to the product between the force applied and the distance over which the force is applieds, so in this case:

`W=Fd=(3 N)(9 m)=27 J`

And the power of the machine is equal to the ratio between the work done by the machine and the time taken:

`P= (W)/(t)= (27 J)/(8 s)=3.38 W`