98.6k views
0 votes
May I please have help with this math problem?

which of the following statements are true if Parabola 1 has the equation f(x)=x2+4x+3 and Parabola 2 has a leading coefficient of 1 and zeros at x = -5 and x = 1. (multiple things may apply)
1. Parabola 1 and Parabola 2 have a zero in common.
2. Parabola 1 and Parabola 2 have the same line of symmetry.
3. Parabola 1 crosses the y-axis higher than Parabola 2.
4. Parabola 1 has a lower minimum than Parabola 2.

User Siwalikm
by
8.5k points

1 Answer

2 votes
Parabola 1:
f (x) = x2 + 4x + 3
f (x) = (x + 1) (x + 3)
intersection with y:
f (0) = (0) ^ 2 + 4 (0) +3
f (0) = 3
Axis of symmetry:
f '(x) = 2x + 4
2x + 4 = 0
x = -4 / 2
x = -2
Minimum of the function:
f (-2) = (- 2) ^ 2 + 4 * (- 2) +3
f (-2) = - 1

Parabola 2:
g (x) = (x + 5) (x-1)
g (x) = x ^ 2 - x + 5x - 5
g (x) = x ^ 2 + 4x - 5 intersection with y:
g (0) = (0) ^ 2 + 4 (0) - 5
g (0) = - 5
Axis of symmetry:
g '(x) = 2x + 4
2x + 4 = 0
x = -4 / 2
x = -2
Minimum of the function:
g (-2) = (- 2) ^ 2 + 4 * (- 2) - 5
g (-2) = - 9

Answer:
3. Parabola 1 crosses the y-axis higher than Parabola 2.
2. Parabola 1 and Parabola 2 have the same line of symmetry.
User Sharjeel
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories