Question

Air in a closed cylinder is heated from 25 degree to 36 degree. If the initial pressure is 3.80 atm what is the final pressure ?

Answer 1

Aww man, I love these types of problems!!!
So, it's a simple formula:
P1*V1/T1=P2*V2/T2

In this case, we remove V(volume) as there is none listed, leaving this:
P1/T1=P2=T2

Think you got it from here? All you gotta do is plug in the numbers and solve
If you have any further problems, just let me know!!

Answer 2

5.47 atm

Step-by-step explanation:

We have an initial state in which the air is at a temperature of 25 degrees and a pressure of 3.80 atm

We also have a final state in which the temperature is 36 degrees and we have to find out the pressure

For two different states it meets the following equation

`(P_1.V_1)/(T_1)=(P_2.V_2)/(T_2)`

As we are told that the air is in a closed cylinder the volume is always constant, it is the same on both sides (
`V_1=V_2`) so we can simplify it and the equation is as follows

`(P_1)/(T_1)=(P_2)/(T_2)`

Now we clear the final pressure (
`P_2`)

`(P_1)/(T_1).T_2=P_2\\\\(3.80atm)/(25\ºC).36\ºC=P_2\\\\5.47 atm= P_2`

The final pressure is 5.47 atm