Question

What is the solution to the equation below?3log_4x=log_43 2+log_4 2

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Answer 1

`(3\log _4\left(x\right))/(3)=(\log _4\left(32\right))/(3)+(\log _4\left(2\right))/(3)`
Simplify

`\log _4\left(x\right)=(\log _4\left(32\right)+\log _4\left(2\right))/(3)`

`\log _4\left(x\right)=1`
Apply log rule

`\log _4\left(x\right)=\log _4\left(4\right)`
Answer:

`x=4`