51.5k views
3 votes
Use the discriminant to determine the number and type of solutions for the following equation. 12x2 + 10x + 5 = 0

A two irrational solutions
B one rational solution
C zero real solutions
D two rational solutions

User Giammin
by
8.6k points

2 Answers

3 votes
Zero real solutions I just did the test
User Leonardo Dagnino
by
7.6k points
5 votes
discriminant D is given by:
D=b²-4ac
Implication of discriminant is as follows:

D<0 two zeros that are complex conjugate
D=0 one real zero of multiplicity 2
D>0 two distinct real zers
D= (+ve perfet square) two distinct rational zeros
From:
12x^2+10x+5=0
plugging in the equation we get:
10²-4×12×5
=100-240
=-140
thus
D<0

Answer is:
A two irrational solutions
User Avram Score
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories