Let us think about the trigonometric functions. If we have a right triangle with an angle we call x. Then we define the trigonometric functions as follows:
cos x = adj/hyp
sin x = opp/hyp
tan x = opp/adj
Where opp is the measure of the side opposite the angle x, adj is the measure of the side adjacent to angle x and hyp is the hypotenuse (the longest side).
We are told that cos x = 1/4 which means that the ratio of the side adjacent to the hypotenuse is 1/4. So let’s make adjacent = 1 and the hypoytenuse = 4.
We now have two sides of the right triangle but are missing the third. We use the Pythagorean theorem to find the third side. The Pythagorean Theorem says:
![a^(2) + b^(2) = c^(2)](https://img.qammunity.org/2019/formulas/mathematics/college/3byu32yniwf4k67ty0w3p5iut2e0wsjpqf.png)
where and b are the lengths of the legs of a right triangle and c is the hypotenuse. For our triangle c = 4, a = 1 and b is the side we don’t know. We could have made b = 1 and solved for a instead since a and b are both legs and can be used interchangeably.
So we end up with the following:
![1^(2)+ b^(2) = 4^(2) 1+b^(2)=16 b ^(2)=15 b= √(15)](https://img.qammunity.org/2019/formulas/mathematics/high-school/k4p9j2zdhm88592ufph3g9mhgvj9qa25zv.png)
This means that the opposite side =
![√(15)](https://img.qammunity.org/2019/formulas/mathematics/high-school/xi9yt31mq1wwcbevb0o9u7s4x5gblxch96.png)
As a reminder:
opp =
![√(15)](https://img.qammunity.org/2019/formulas/mathematics/high-school/xi9yt31mq1wwcbevb0o9u7s4x5gblxch96.png)
Adj = 1
hyp = 4
Therefore we find sin x and tan x as follows:
sin x = opp/hyp =
![( √(15) )/(4)](https://img.qammunity.org/2019/formulas/mathematics/high-school/uh4v07sh655tb3kh2kl1u3spwu49ar54p8.png)
tan x = opp/adj =
![( √(15) )/(1)= √(15)](https://img.qammunity.org/2019/formulas/mathematics/high-school/i0m90tfcu0e43krowkmzez3ox0buu3vgwz.png)