Final answer:
The electric potential of a 2.2 µC charge at a distance of 6.3 m is 3.14 × 10^6 V. At a distance of 99 m, the electric potential is 2.02 × 10^4 V.
Step-by-step explanation:
To calculate the electric potential, we can use the equation V = kQ/r, where V is the electric potential, k is Coulomb's constant (8.99 × 10^9 N • V^-2 • m^2 • C^-2), Q is the charge, and r is the distance from the charge.
For a charge of 2.2 µC at a distance of 6.3 m, we can plug in the values to find:
V = (8.99 × 10^9 N • V^-2 • m^2 • C^-2)(2.2 × 10^-6 C)/(6.3 m) = 3.14 × 10^6 V
Similarly, for a distance of 99 m, the calculation would be:
V = (8.99 × 10^9 N • V^-2 • m^2 • C^-2)(2.2 × 10^-6 C)/(99 m) = 2.02 × 10^4 V