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Zn+2HCl=ZnCl2+H2 how many moles of ZnCl2 will be produced from 61.0 g of ZnCl2, assuming HCl is available in excess?

User Krflol
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2 Answers

6 votes

how did you get 136.28

User Alexey Primechaev
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Answer:
127.15 g of ZnCl₂

Solution:
The balance chemical equation is as follow,

Zn + 2 HCl → ZnCl₂ + H₂

According to equation,

65.38 g (1 mole) of Zn produced = 136.28 g (1 mole) of ZnCl₂
So,
61.0 g of Zn will produce = X g of ZnCl₂

Solving for X,
X = (61.0 g × 136.28 g) ÷ 65.38 g

X = 127.15 g of ZnCl₂
User Xithias
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