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If √6b+4=20, then what is the value of b

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D:6b+4\geq0\to b\geq-(2)/(3)\\\\√(6b+4)=20\ \ \ |^2\\\\(√(6b+4))^2=20^2\\\\|6b+4|=400\to 6b+4=400\ \vee\ 6b+4=-400\ \ |-4\\\\6b=396\ \vee\ 6c=-404\ \ \ |:6\\\\b=66\in D\ \vee\ b=-67(2)/(3)\\otin D


Answer:\ b=66
User Andy Triggs
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